$i++ problem understanding

Currently I am studying PHP.

I can understand the following :
$a = 10;
$b = $a++;
print("$a, $b");
will print 11, 10 on the screen.
because when $b = $a++ first thing that happens is $b = $a
and then $a = $a + 1. I am willing to and can accept that.

But much harder to accept is and I fail to see the logic in it,
is the following :
$i = 1;
print($i++);
This will print 1 and only afterward will the value of $i be increased
by 1. It is between (), so logic tells me first $i++ and then print.

Can anyone help me understand this or see the logic in it ?

thanx,

Pugi!
Received on Tue Oct 18 02:32:06 2005