Re: $i++ problem understanding

Pugi! wrote:
> Currently I am studying PHP.
>
> I can understand the following :
> $a = 10;
> $b = $a++;
> print("$a, $b");
> will print 11, 10 on the screen.
> because when $b = $a++ first thing that happens is $b = $a
> and then $a = $a + 1. I am willing to and can accept that.
>
> But much harder to accept is and I fail to see the logic in it,
> is the following :
> $i = 1;
> print($i++);

its the same as in $b=$a++; the ++ comes last.

> This will print 1 and only afterward will the value of $i be increased
> by 1. It is between (), so logic tells me first $i++ and then print.
>
> Can anyone help me understand this or see the logic in it ?
>
>
> thanx,
>
> Pugi!
Received on Tue Oct 18 02:32:07 2005