Re: why "g".count('')==2 ?
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Re: why "g".count('')==2 ?

From: Fredrik Lundh <fredrik@pythonware.com>
Date: Sat Mar 11 2006 - 13:37:05 CET



"ygao" wrote:



> my question is as title!



my answer as code:



>>> s = "g"


>>> t = ""


>>> s[0:0+len(t)] == t


True


>>> s[1:1+len(t)] == t


True



</F>


Received on Sun Apr 30 11:33:45 2006