Re: Function params with **? what do these mean?

In article <r56u12pb4ajvhshvh40slb80di1bfeiagr@4ax.com>,
Dave Hansen <iddw@hotmail.com> wrote:
>On 20 Mar 2006 12:46:43 -0800 in comp.lang.python, "J Rice"
><rice.jeffrey@gmail.com> wrote:
>>
>>I'm sorry for such a basic question, but I haven't been able to phrase
>>a search that gets me an answer and my books are totally silent on
>>this. I have seen a number of python function defs that take
>>parameters of the form (**param1). Looks like a pointer... but my
>>books on python (basic as they are) don't make a mention. What is
>>this?
>
>It's a way of accepting a varying number of named arguments. In the
>function, the parameter becomes a dictionary with parameter names as
>the keys corresponding to the passed parameter values.
>
>It's harder to explain than understand. Try playing with the
>following function in the python interpreter:
>
> def test(a,b='b', *c, **d):
> print a,b,c,d

Personally, I think it's a Good Idea to stick with the semi-standard
names of *args and **kwargs to make searching easier...

-- 
Aahz (aahz@pythoncraft.com)           <*>         http://www.pythoncraft.com/
"19. A language that doesn't affect the way you think about programming,
is not worth knowing."  --Alan Perlis