Re: Puzzled (4^162 mod 100)

From: Arturo Magidin <magidin@math.berkeley.edu>
Date: Mon Apr 03 2006 - 03:24:29 CEST

In article <e0pskq$5he$1@agate.berkeley.edu>,
Arturo Magidin <magidin@math.berkeley.edu> wrote:

>>The multiplicative identity of this subgroup is 76.
>
>It's not a "subgroup" because there is no overgroup.

Okay, my mistake. Apparently, "subgroup" is the accepted nomenclature
for a subsemigroup which happens to be a group under the induced
operation. Sorry about that.

-- 
======================================================================
"It's not denial. I'm just very selective about
 what I accept as reality."
    --- Calvin ("Calvin and Hobbes")
======================================================================
Arturo Magidin
magidin@math.berkeley.edu

Received on Mon May 1 01:54:50 2006

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Re: Puzzled (4^162 mod 100)