Re: multi-key encryption algorithm is meaningful?

I used simply Chinese remainder theorem.
You can find it after few minutes.

User choose both plaintexts,key arbitrarily.
constraint is just each key must be mutually relatively prime.
and ciphertext size is 2 times to the key size based on empirical test.
I think now one-time pad is better than this.
Received on Tue Jan 17 16:50:56 2006